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Q.

In the expansion of 1+x+7x11, the term not containing x is

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a

r=0511Cr11rC2r7r

b

r=1511Cr11rC112r7r

c

r=0511Cr11rC112r7r

d

r=15r  c  11 

answer is C.

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Detailed Solution

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1+x+7x11=7+x+x2x11

So, we have to find the coefficient of x11 in 7+x+x211

Now 7+x+x211

       =(7+x)+x211=11C0(7+x)11+11C1(7+x)10x2+11C2(7+x)9x4+

    Required coefficient =11C0+i1C1×10C9×7+11C2×9C7×72+11C3×8C5×73+11C4×7C3×74+11C5×6C1×75 =r=0511Cr11rC112r7r

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