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In the experiment of Ohm’s law, a potential difference of 5.0V is applied across the end of a conductor of length 10.0 cm and diameter of 5.00mm. The measured current in the conductor is 200 A. The maximum permissible percentage error in the resistivity of the conductor is :

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8.4

3.9

3.0

7.5

answer is B.

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Detailed Solution

$R = \frac{ρ l}{A} Δ v = 0.1 v$
$Δ l = 0.1 c m Δ I = 0.01 A Δ d = 0.01 m m \frac{Δ ρ}{ρ} \times 100 = \frac{Δ R}{R} \times 100 + \frac{Δ l}{l} \times 100 + 2 \frac{Δ r}{r} \times 100$

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