In the explanation of chemical bonding of diborane, Valence bond theory predicts that each boron produces hybrid orbitals whose wave functions are obtained from wave function of 2s orbitals and 2p orbitals. Number of atomic wave functions with n=2 and $l = 1$ required to form hybrid orbitals in one Boron atom is ‘p’ and total number of hybrid orbitals involved in two banana bonds is ‘q’ in diborane. What is the value of (p +q)?

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Detailed Solution

Boron atom is $s p^{3}$ hybridizes in diborane. Three 2p orbitals are required. Each banana bons involves two hybrid orbitals.

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