In the figure, a very large plane sheet of positive charge is shown. $P_{1} and P_{2}$ are two points at distance l and 2l from the charge distribution. If $σ$ is the surface charge density, then the magnitude of electric fields $E_{1} and E_{2}$ at $P_{1} and P_{2}$ respectively are :

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$E_{1} = \frac{2 σ}{ε_{0}}, E_{2} = \frac{σ}{ε_{0}}$

$E_{1} = E_{2} = \frac{σ}{2 ε_{0}}$

$E_{1} = E_{2} = \frac{σ}{ε_{0}}$

$E_{1} = \frac{σ}{ε_{0}}, E_{2} = \frac{σ}{2 ε_{0}}$

answer is C.

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Detailed Solution

As the sheet is very large $\hat{E}$ is independent of distance from it.

Thus $E_{1} = E_{2} = \frac{σ}{2 ε_{0}}$

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