In the figure ,$\overline{AB}=3\widehat{i}-\widehat{j},\overline{AC}=2\widehat{i}+3\widehat{j}and\overline{DE}=4\widehat{i}-2\widehat{j},$then the area of the shaded region in square units is 

$\begin{array}{l}\overline{BC}=\overline{AC}-\overline{AB}\\ =-\widehat{i}+4\widehat{j}\\ \mathrm{Re}q.area=\frac{1}{2}\left|\overline{ED}\times \overline{EB}+\overline{EC}\times \overline{ED}\right|\\ =\frac{1}{2}\left|\overline{ED}\times \left(\overline{EB}-\overline{EC}\right)\right|\\ =\frac{1}{2}\left|\overline{ED}\times \overline{CB}\right|\\ =\left|7\overline{K}\right|\\ =7\end{array}$