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In the figure ABC is the cross-section of a right angled prism and BCDE is the cross-section of a glass slab. The value of $θ$ . So that light Incident normally on the face AB does not cross the face BC is (given $\sin^{- 1} (\frac{3}{5}) = 37^{\circ})$

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$θ$ $\geq$ 37^o

$θ$ < 37^o

$θ$ < 53^o

$θ$ $\geq$ 53^o

answer is A.

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Detailed Solution

The light will not cross BC, if the angle of incidence is greater than the critical angle.
$i > \sin^{- 1} [\frac{6 / 5}{3 / 2}]$

$\Rightarrow i > 53^{o}$

From ABC $i = 90^{o} - θ$
$∴$ $θ$ < 37^o

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