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Q.

In the figure ABC is the cross-section of a right angled prism and BCDE is the cross-section of a glass slab. The value of $θ$ so that light incident normally on the face AB does not cross the face BC is $(Given \sin^{- 1} 3 / 5 = 37 °)$

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a

$θ \geq 37 °$

b

$θ < 37 °$

c

$θ > 53 °$

d

$θ \geq 53 °$

answer is A.

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Detailed Solution

$\sin θ_{C} = \frac{μ_{R}}{μ_{D}} = \frac{6 / 5}{3 / 2} = \frac{4}{5} r_{1} = 0 ° \Rightarrow r_{2} = < B = 90 ° - θ N o w, r_{2} > θ_{c} o r \sin r_{2} > \sin θ_{c} ∴ \sin (90 ° - θ) > \frac{4}{5} o r \cos θ > \frac{4}{5} \cos 37 ° > \frac{4}{5}$

From Eq.(i), we see that $θ < 37 °$

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