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In the figure, $AD ∥ BC$ and $AD = BC$ . Then $ΔABD ≅ ΔCDB$ by congruence postulate.

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SSS

ASA

AAS

SAS

answer is D.

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Detailed Solution

Given,

AD ∥ BC

and

AD = BC

in figure,
Question Image

ΔABD

and

ΔCDB,

AD = BC

(given)

∠ BDA = ∠ DBC

(Alternate angles)

BD = BD

(common side)

∴ ΔABD ≅ ΔCDB

(By SAS postulate)
Hence the option

4

is correct.

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