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In the figure are shown the lines of action and moment arms of two forces about the orign O. Imagining these forces to be acting on a rigid body pivoted at O, all vectors shown being in the plane of the figure, the magnitude and direction of the resultant torque will be :

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$(F_{2} r_{2} \sin θ_{2} - F_{1} r_{1} \sin θ_{1})$ out of the of plane of the page

$(F_{1} r_{1} \sin θ_{1} - F_{2} r_{2} \sin θ_{2})$ Out of the plane of the page

$(F_{2} r_{2} \sin θ_{2} - F_{1} r_{1} \sin θ_{1})$ into the of plane of the page

Zero

answer is B, C.

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Detailed Solution

Torque is given by cross product of position vector and the force

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