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In the figure given a ray of light is incident from medium A to medium B, Refractive Index of medium B in relation to medium A is [[1]].

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Detailed Solution

In the figure given a ray of light is incident from medium A to medium B, Refractive Index of medium B in relation to medium A is

\frac{\sqrt{3}}{\sqrt 2}

.
Snell’s Law states that in a given pair of media, the ratio of the sines of the angle of incidence

θ_{1}

and angle of refraction

θ_{2}

is equivalent to the ratio of refractive indices (

n

) of two media.
Given,
Angle of incidence,

i = 60 °

Angle of refraction,

r = 45 °

From the figure,

n = \frac{\sin i}{\sin r}

= \frac{\sin 60 °}{\sin 45 °}

= \frac{\sqrt{3}}{\sqrt 2}

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