In the figure given below, a block of mass M = 490g placed on a frictionless table is connected with two springs having same spring constant $(K = 2 N m^{- 1})$ . If the block is horizontally displaced through ' X ' m then the number of complete oscillations it will make in 14 $π$ seconds will be ____.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is 20.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The given case will have an effective spring constant of 2K.

We know, time period of a spring mass system is given by

$T = 2 π \sqrt{\frac{m}{k_{eff}}}$

$∴ T = 2 π \sqrt{\frac{m}{2 K}}$

$= 2 π \sqrt{\frac{0.49}{4}} = 2 π \times \frac{0.7}{2} n = \frac{14 π}{π \times 0.7} = 20$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test