In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 sec is

Velocity between t = 0 and t = 2 sec

$\Rightarrow {\mathrm{v}}_1 = \frac{\mathrm{dx}}{\mathrm{dt}} = \frac{4}{2} = 2 \mathrm{m}/\mathrm{s}$

Velocity at t = 2 sec, ${\mathrm{v}}_{\mathrm{f}}= 0$

Impulse = Change in momentum = m (${\mathrm{v}}_{\mathrm{f}}-{\mathrm{v}}_{\mathrm{f}}$)

    0.1(0-2) = -0.2 $\mathrm{kg} \mathrm{m} {\sec }^{-1}$