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In the Figure given below two masses m and m' are tied with a thread passing over a pulley, m' is on a frictionless horizontal surface. If acceleration due to gravity is g, the acceleration of m' in this arrangement will be:

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mg/(m - m')

mg/(m + m')

mg/m'

answer is B.

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Detailed Solution

$Acceleration = \frac{Net force in the direction of a}{Total mass} = \frac{mg}{m + m^{'}}$

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