In the figure, given below, $2AD=AB.P$ is mid-point of A B . Q IS mid of-point of DR and  $PR\parallel BS$, then  $AQ\parallel BS$.

 

Concept: Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

Given: $PR\parallel BS, P$ is mid point of AB and Q  is mid point of DR.

Also, 

$2AD=AB$

That is, A is mid point of  PD.

Now, In $∆DPR$, A  is mid point of PD and  Q is mid point of  DR.

Thus, by converse of mid point theorem,  $AQ\parallel PR$. since $PR\parallel BS$,

hence,  $AQ\parallel PR\parallel BS$

Therefore, the given statement is true and option 1 is correct.