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Q.

In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th bright fringe on the other side, as measured from Q. If the wavelength of the light used is $6000 \times 10^{- 10} m$ , then $S_{1} B$ will be equal to

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a

$6.6 \times 10^{- 6} m$

b

$3.138 \times 10^{- 7} m$

c

$3.144 \times 10^{- 7} m$

d

$6 \times 10^{- 6} m$

answer is A.

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Detailed Solution

P is the position of 11th bright fringe from Q. From central position O, P will be the position of 10th bright fringe.

Path difference between the waves reaching at P $= S_{1} B = 10 λ = 10 \times 6000 \times 10^{- 10} = 6 \times 10^{- 6} m$

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In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th bright fringe on the other side, as measured from Q. If the wavelength of the light used is 6000×10−10m, then S1B will be equal to