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In the figure  M1=4M2The pulleys are smooth and light. At time t = 0, the system is at rest. If

            the system is released, the acceleration of mass M1 is

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a
g/2
b
g/8
c
g/4
d
g

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detailed solution

Correct option is C

M1g2T=M1a      1 TM2g=M22a2 solving1&2        1M1g2T=M1a 2×22T2M2g=2M22a M1g2M2g=M1a+4M2a M1=4M2 4M2g2M2g=4M2a+4M2a 2M2g=8M2a a=g4

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