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In the figure masses $400 k g$ and $100 k g$ are fixed. How much work must be done to move a $1 k g$ mass from point $A$ to point $B$ ?

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$7.5 \times 10^{- 9} J$

$- 7.5 \times 10^{- 9} J$

$6.5 \times 10^{- 9} J$

$- 6.5 \times 10^{- 9} J$

answer is C.

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Detailed Solution

$W = U_{f} - U_{i} = U_{B} - U_{A}$

$= m V_{B} - m V_{A} (V = gravitational potential)$

$= m (V_{B} - V_{A})$

$= (1) [- \frac{100}{2} - \frac{400}{8} + \frac{100}{8} + \frac{400}{2}] (6.67 \times 10^{- 11})$

$= 7.5 \times 10^{- 9} J$

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