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Q.

In the figure (not drawn to scale), ABC and DEF are two triangles, CA is parallel to FD and CF, BE is a straight line. Find the value of x+y.


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a

185°

b

134°

c

158°

d

176° 

answer is A.

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Detailed Solution

∠FCA=∠BFD
⇒x = 51°  ..... (Corresponding angles)
Now in △ABC , we have
y=51°+83°.....By using exterior angle property
⇒y=134°
So, x+y=51°+134°
 =185°
So, option 1 is the correct option.
 
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