AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

In the figure PA and PB are two tangents drawn from an external point P to a circle with center C of radius 4 cm. If PA⊥PB then the length of each tangent is:

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

3 cm

4 cm

5 cm

6 cm

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The correct answer is 4cm.
Radius of circle= 4cm
Using the figure,

⇒ C A = C B = 4 c m

The tangents drawn to the circle from the external point are equal:

⇒ P A = P B

Given:

P A ⊥ P B

Now, the radius of the circle is perpendicular to the tangent.
We get:

C A ⊥ P A

and

C B ⊥ P B

The quadrilateral CAPB is a square as all angles are 90 degrees and adjacent sides are equal.

⇒ C A = C B = P A = P B = 4 c m

Therefore, the length of tangent is 4cm.
The answer is option 2.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!