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In the figure, QT⊥PR,∠TQR=40∘ and ∠SPR=30∘. Find ∠QRT.

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110

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answer is A.

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Detailed Solution

⇒ ∠TQR + ∠QRT + ∠RTQ = 180

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(angle sum property)
QT⊥PR and ∠TQR=40

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(Given)
⇒ 40

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+ ∠QRT + 90

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= 180

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⇒∠QRT = 180

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−130

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⇒∠QRT=50

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∴ ∠TRS=50

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