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In the figure show, if coefficient of friction is $μ$ , then $m_{2}$ will start moving upwards if

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$\frac{m_{1}}{m_{2}} > \sin θ - μ \cos θ$

$\frac{m_{1}}{m_{2}} > \sin θ + μ \cos θ$

$\frac{m_{1}}{m_{2}} > μ \sin θ - \cos θ$

$\frac{m_{1}}{m_{2}} > μ \sin θ + \cos θ$

answer is B.

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Detailed Solution

$m_{1} g > m_{2} g \sin θ + μ m_{2} g \cos θ \frac{m_{1}}{m_{2}} > \sin θ + μ \cos θ$

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