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Q.

In the figure shown, after the switch  ‘S’ is turned from position ‘A’ to position ‘B’ the energy dissipated in the circuit is xyCE2, then x+y is

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answer is 11.

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Detailed Solution

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Energy stored in the system initially

Ui=12CE2

Uf=12Q2Ceq=CE22×4C=12CE24

As Q=CE, and Ceq=4C

ΔU=12CE2×34=38CE2=38Q2C

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