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In the figure shown below, the charge on the left plate of the $10 μ F$ capacitor is $- 30 μ C$ . The charge on the right place of the $6 μ F$ capacitor is

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$- 12 μ c$

$+ 12 μ c$

$- 18 μ c$

$+ 18 μ c$

answer is D.

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Detailed Solution

Equivalent Capacitance of $6 μ F$ and $4 μ F$
capacitors $= 10 μ F$
Change on $6 μ F$ capacitor
$= \frac{6}{10} \times 30 = 18 μ C$

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