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In the figure shown, blocks A and B move with velocities $v_{1}$ and $v_{2}$ along horizontal direction. Find the ratio of $v_{1} / v_{2}$

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$\frac{\sin θ_{2}}{\sin θ_{1}}$

$\frac{\sin θ_{1}}{\sin θ_{2}}$

$\frac{\cos θ_{1}}{\cos θ_{2}}$

$\frac{\cos θ_{2}}{\cos θ_{1}}$

answer is C.

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Detailed Solution

From figure $l_{1} + l_{2} = C o r \frac{d l_{1}}{d t} + \frac{d l_{2}}{d t} = 0$

$- v_{1} \cos θ_{1} + v_{2} \cos θ_{2} = 0 (o r) \frac{v_{1}}{v_{2}} = \frac{\cos θ_{2}}{\cos θ_{1}}$

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