In the figure shown, each capacitor is 1 μF and the resistors are indicated. Q1 and Q4 are charges on the capacitors C1 and C4 and are respectively under steady condition. Then Q1=____________μC.

Under steady state condition, the potential difference across AB=6V5Ω+1Ω×5Ω=5VEquivalent capacitance of C1 and C4 will be 0.5 μF.charges on them will be 50.5 = 2.5 μC

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In the figure shown, each capacitor is $1 μF$ and the resistors are indicated. Q₁ and Q₄are charges on the capacitors C₁and C₄ and are respectively under steady condition. Then Q₁=____________ $μC$ .

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Detailed Solution

Under steady state condition, the potential difference across AB
$= (\frac{6 V}{5 Ω + 1 Ω}) \times 5 Ω = 5 V$

Equivalent capacitance of C₁ and C₄ will be 0.5 $μF$ .

charges on them will be $5 (0.5) = 2.5 μC$

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