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In the figure shown , for maximum range R if $h_{1} = 4 H$

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$h_{2} = 2 H$

$R = 10 H$

$R = 20 H$

$h_{2} = 5 H$

answer is B, C.

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Detailed Solution

R = $\sqrt{2 g h_{2}} \times \sqrt{\frac{2 (10 H - h_{2})}{g}}$ =2 $\sqrt{10 H h_{2} - {h^{2}}_{2}}$

For maximum R , $\frac{d R}{d h_{2}} = 0 \Rightarrow h_{2} = 5 H a n d R = 10 H$

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