Q.

In the figure shown m1=1kg,m2=2kg , pulley is ideal. At t = 0, both masses touches the ground and string is taut. A force F=2t is applied to pulley (t is in second) then (g=10m/s2)

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a

m2  is lifted off the ground at t = 20 sec

b

work done by tenstion in the string of m1 beforem2 is lifted off the ground is 1250 joule

c

m1 is lifted off the ground at t = 10 sec

d

work done by tenstion in the string of m1 beforem2 is lifted off the ground is zero

answer is A, B, C.

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Detailed Solution

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att=20s,F=40N,T=20N

att=10s,F=20N,T=10N

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