In the figure shown, the capacity of the condenser C is $2 \mu F$. If the circuit is in steady state, the current in $2\Omega$ resistor is

No current flows through the capacitor branch in steady state. Total current supplied by the battery,

$\mathrm{i}=\frac{6}{2.8+1.2}=\frac{3}{2}$

Current through $2\Omega$ resistor $=\frac{3}{2}\times \frac{3}{5}=0.9\mathrm{A}$