In the figure shown, the coefficient of static friction between B and the wall is 2/3 and the coefficient of kinetic friction between B and the wall is 1/3. Other contacts are smooth. The minimum force ‘F’ required to lift B, up is F₀. Now if the force applied on A is slightly increased than F₀, then find the acceleration of B. Mass of A is 2m and the mass of B is m. Take tan $θ$ = 0.75 (g = 9.8 m/s²)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 1.34.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

If normal force between A & B is N, for pending upward motion of block B of mass ‘m’ with help of static friction,
Ncosθ = mg + $µ_{s} Nsin θ$
If force is slightly increased above this value, the friction becomes kinetic.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!