In the figure shown, the wires P₁Q₁ and P₂Q₂ are made to slide on the rails with same speed of 5cms^-1. In this region a magnetic field of 1 tesla exists. The electric current in  $9\Omega$  of resistance is

 

Induced emf = Blv

If both wires slide towards left
$E=\frac{e_1{r}_2+e_2{r}_1}{r_1+r_2}=\frac{\left(2\right)\left(2\right)+\left(2\right)\left(2\right)}{\left(2+2\right)}mV=2mV$

$r_{net}=\frac{r_1{r}_2}{r_1+r_2}=1\Omega$
 $I=\frac{E}{R+r_{net}}=\frac{2}{10}mA=0.2mA$   

If both wires move opposite direction
$E=\frac{e_1{r}_2-e_2{r}_1}{r_1+r_2}=\frac{\left(2\right)\left(2\right)-\left(2\right)\left(2\right)}{\left(2+2\right)}mV=0$

$r_{net}=\frac{r_1{r}_2}{r_1+r_2}$
 $I=\frac{E}{R+r_{net}}=0$