In the figure shown, what is the current (in Ampere) drawn from the battery ? you are given R1=15Ω,R2=10Ω,R3=20Ω,R4=5Ω,R5=25Ω,R6=30Ω,E=25V

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In the figure shown, what is the current (in Ampere) drawn from the battery ? you are given

$R_{1} = 15 Ω, R_{2} = 10 Ω, R_{3} = 20 Ω, R_{4} = 5 Ω, R_{5} = 25 Ω, R_{6} = 30 Ω, E = 25 V$

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13/24

7/18

9/32

15/32

answer is D.

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Detailed Solution

$A p p l y s e r i e s a n d p a r a l l e l c o m b i n a t i o n o f r e s i s t o r s 20 Ω, 5 Ω a n d 25 Ω a r e i n s e r i e s \Rightarrow R_{1} = 20 + 5 + 25 = 50 Ω \Rightarrow R_{1} = 50 Ω i s p a r a l l e l w i t h 10 Ω \Rightarrow R_{2} = \frac{50 (10)}{50 + 10} = \frac{500}{60} = \frac{25}{3} Ω \Rightarrow R_{2} = \frac{25}{3} Ω i s i n s e r i e s w i t h 15 Ω a n d 30 Ω R_{e f f} = \frac{25}{3} + 15 + 30 = \frac{160}{3} Ω i = \frac{Voltage}{Net resistance of the circuit} = \frac{25}{\frac{160}{3}} = \frac{15}{32}$