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Q.

In the figure, the block ‘B’ of mass ‘m’ starts from rest at the top of a wedge ‘W’ of mass ‘M’. All surfaces are without friction ‘W’ can slide on the ground ‘B’ slides down on to the ground, moves along it with a speed ‘V’ has an elastic collision with the wall, and climbs back on to ‘W’

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a

From the beginning, till the collision with the wall, the centre of mass of ‘B’ plus ‘W’ does not move horizontally

b

After the collision, the centre of mass of ‘B’ plus ‘W’ moves with the velocity  2mVm+M

c

When ‘B’ reaches its highest position of W, the speed of W is  2mVm+M

d

When B reaches its highest position of W, the speed of W is   mVm+M

answer is A, B, C.

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Detailed Solution

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a) Force acting block on the horizontal direction is zero. Since block and wedge both are initially at rest. So velocity of Com does not move horizontally

b)  VCm=mVmVM+m=2mVm+M

c) When ‘B’ reaches it highest position of W, the speed of W is equal to velocity of com i.e., 

VCm=2mVm+M

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