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Q.

In the figure the voltmeter shows reading of 20 V. The battery has a voltage of $U_{0} = 100 V$ no internal resistance. Find the ratio of the current going through right part of the potentiometer to the current going through the voltmeter, if the jockey divides potentiometer into ratio 1 : 2, and bigger resistance of the potentiometer is located to the right of jockey.

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answer is 2.

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$\frac{80}{2 R} = \frac{20}{R} + i_{2}$
$i_{2} = \frac{20}{R}; i_{1} = \frac{80}{2 R} = \frac{40}{R}$
$\frac{i_{1}}{i_{2}} = 2$

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