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Q.

In the figure, AB  is diameter and PQ  is tangent.  If PQ=5cm  and PA=1cm , then the radius of circle is

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a

13cm

b

11cm

c

12cm

d

7cm

answer is B.

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Detailed Solution

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In ΔPQO,PQO=90°

PO2=PQ2+OQ2

(PA+AO)2=PQ2+OQ2

(1+r)2=52+r2

1+r2+2r=25+r2

1+2r=25

2r=24

r=12cm .

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