In the following circuits, pn junction, diodes D₁, D₂ and D₃ are ideal for the following potential of A and B, the correct increasing order of resistance between A and B will be

(i) -10 V, 5 V (ii)  -5 V, -10 V (iii) -4 V, -12 V

$\left(i\right) V_A=-10 V and V_B=-5 V$

Diodes D₁ and D₃ are reverse biased and D₂ is forward biased.

$\Rightarrow R_{AB}=R+\frac{R}{4}+\frac{R}{4}=\frac{3}{2}R$

$\left(ii\right) V_A=5 V and V_B=-10 V$

Diodes D₂ is reverse biased and D₁ and D₃ are forward biased.

$\Rightarrow R_{AB}=\frac{R}{4}+\frac{R}{2}+\frac{R}{4}=R$

(iii) In this case, equivalent resistance between ,A and B is also R.

Hence correct order is (ii) = (iii) < (i).