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Q.

In the following data the median of the runs scored by 60 top batsmen of the world in one-day international cricket matches is 5000.


Runs scored

Frequency

2500-3500

5

3500-4500

X

4500-5500

Y

5500-6500

12

6500-7500

6

7500-8500

2


The missing frequencies x and y are ____ and ____, respectively.


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Detailed Solution

The missing frequencies x and y are 15 and 20, respectively.
Given:

Runs scored

Frequency

2500-3500

5

3500-4500

X

4500-5500

Y

5500-6500

12

6500-7500

6

7500-8500

2

We know that the formula of median is
 Median =l+ h× N 2 cf f  
where, l  =lower limit of the median class, h  =size of the median class, f  = frequency of the median class, N  = sum of frequencies and cf   =cumulative frequency of the class just preceding the median class.
The cumulative frequency distribution table will be:

Runs scored

Frequency

Cumulative frequency

2500-3500

5

5

3500-4500

x

5+x

4500-5500

y

5+x+y

5500-6500

12

5+x+y+12=17+x+y

6500-7500

6

17+x+y+6=23+x+y

7500-8500

2

23+x+y+2=25+x+y=N

 

N=Σfi=60 (given)

 

25+x+y=60 x+y=35...... 1  
Calculating median:
 Median =l+ h× N 2 cf f  
  5000=4500+ 1000× 60 2 5+x y  
  500=1000× 305x y  
  y=502x....... 2  
Solve equations 1 and 2, we get x=15,y=20  .
Thus, the missing frequencies x and y are 15,20.
 
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