Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

In the following figure, ABCD is a trapezium with AB || DC, AB=18 cm, DC=32 cm and distance between AB and DC is 14cm. If arcs of equal radii 7 cm with centres A, B, C and D have been drawn, then the area of the shaded region of the figure from the following choices is:


Question Image

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

121  cm 2

b

135  cm 2

c

154  cm 2

d

196  cm 2  

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

It is given that, AB=18 cm, DC=32 cm and distance between AB and DC is 14 cm.
Question ImageObtain the area of a trapezium.
The area of the trapezium is given by,
A=12×Sum of parallel sides×Distanca between parallel sides Here, the distance between the parallel sides is 14 cm.
Substituting the values in the formula, we get,
A=12(AB+CD)14
A=12(18+32)14
A=350cm2
Obtain the area of the circle, we get,
A =π r 2 A =π (7) 2 A =154  cm 2 Thus, from figure the area of the shaded region is,
A s =A A A s =350154 A s =196  cm 2
The area of the shaded region is 196  cm 2 .
Hence, option 4) is correct.
 
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring