In the following Lewis structure of HNO₃
Column – I Column – II
a) O₍₁₎ i) zero
b) O₍₂₎ ii) -1
c) O₍₃₎ iii) +1
(a) (b) (c )
(1) i ii iii
(2) ii i iii
(3) i i ii
(4) iii ii i
The formal charge on Column I, 0(1), 0(2) and 0(3) are given in column II. match the following and choose the correct option from the codes given below.

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answer is C.

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Detailed Solution

In the given molecule,

(1) For 0₍₁₎
Formal charge $= 6 - \frac{1}{2} (4) - 4 = 0$
(2) For 0₍₂₎
Formal charge $= 6 - \frac{1}{2} (4) - 4 = 0$
(3) For0₍₃₎
Formal charge $= 6 - \frac{1}{2} (4) - 6 = - 1$
Thus, the correct match is : $A \to 1, B \to 1, C \to 2$