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Q.

In the following reaction sequence the amount of E
(in gram) formed from 25 moles of aniline is _____.
(Atomic weight in g/mol; H=1,C=12,Br=80,N=14,O=16.The yield (%) corresponding to
the product in each step is given in the parenthesis) 

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answer is 236.

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Detailed Solution

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Moles of aniline = 25
Moles of A=25x0.4=10
Moles of B=10x 0.5=5
Moles of C=5x 0.4 = 2
Moles of D= 2x 0.5 =1
Moles of E=1
Mass of E=1x 236 = 236gram

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