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Q.

In the following reaction, the major product (thermodynamically stable) is
 

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a

CH32C=CH−CH2Br

b

CH3C(Br)CH3CH=CH2

c

BrCH2CHCH3CH=CH2

d

CH2=CCH3CH(Br)CH3

answer is D.

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Detailed Solution

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Kinetically stable compound forms 1,2-addition product whereas thermodynamically stable compound forms 1,4-addition product.

Among the given compounds, only CH32C=CH−CH2Br is 1,4-addition product.

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