In the following reaction :xKMnO4 + y NH3 → KNO3 + MnO2 + KOH + H2Ox and y are

KMn+7O4 → Mn+4O2 - 3e- N-3H3 → N+5O3- + 8e-In balanced equation, coefficient of KMnO4=8 and NH3 is 3.

In the following reaction :xKMnO4 + y NH3 → KNO3 + MnO2 + KOH + H2Ox and y are

KMn+7O4 → Mn+4O2 - 3e- N-3H3 → N+5O3- + 8e-In balanced equation, coefficient of KMnO4=8 and NH3 is 3.

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In the following reaction :
${xKMnO}_{4} + y {NH}_{3} \overset{}{\to} {KNO}_{3} + {MnO}_{2} + KOH + H_{2} O$
x and y are

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x = 4, y = 6

x = 8, y = 3

x = 8, y = 6

x = 3, y = 8

answer is B.

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$\underset{}{K \overset{+ 7}{Mn} O_{4}} \overset{}{\to} \underset{}{\overset{+ 4}{Mn} O_{2}} - 3 e^{-} \underset{}{\overset{- 3}{N} H_{3}} \overset{}{\to} \underset{}{\overset{+ 5}{N} O_{3}^{-}} + 8 e^{-}$

In balanced equation, coefficient of ${KMnO}_{4} = 8$ and ${NH}_{3}$ is 3.

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In the following reaction :xKMnO4 + y NH3 → KNO3 + MnO2 + KOH + H2Ox and y are

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In the following reaction :
${xKMnO}_{4} + y {NH}_{3} \overset{}{\to} {KNO}_{3} + {MnO}_{2} + KOH + H_{2} O$
x and y are