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In the following reactions which is deuterolysis
I) $Al {Cl}_{3} + 3 D_{2} O ⟶ Al (OD)_{3} + 3 DCl$
II) ${CaC}_{2} + 2 D_{2} O ⟶ Ca (OD)_{2} + C_{2} D_{2}$
III) ${Mg}_{3} P_{2} + 6 D_{2} O ⟶ 3 Mg (OD)_{2} + 2 {PD}_{3}$

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I and II only

II and III only

I and III only

I, II and III

answer is D.

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Detailed Solution

During Deuterolysis cleavage of bonds in the compound takes place

AlCl₃ + 3D₂O → A(OD)₃ + 3DCl
CaC₂ + 2D2O → Ca(OD)₂ + C₂D₂
Mg₃P₂ + 6D₂O → Ca(OD)₂ + 2PD₃

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