In the following reactions
a) $8{\mathrm{NH}}_3+3{\mathrm{Cl}}_2⟶6{\mathrm{NH}}_4\mathrm{Cl}{+}^{\mathrm{\prime }}\mathrm{x} \text{'}$
b) ${\mathrm{NH}}_3+3{\mathrm{Cl}}_2{⟶}^{\text{'}}\mathrm{y}\text{ ' }3\mathrm{HCl}$
x and y respectively are:

8NH₃​+3Cl₂​→6NH₄​Cl+N_2​

When ammonia reacts with adequate amount of chlorine then ammonium chloride is formed as a product.

If Cl is taken in excess then NCl₃​ is obtained as a product.

NH₃​+3Cl_2​→NCl₃​+3HCl

X  and Y are N₂ and NCl₃