In the following reaction, $X$ and $Y$ are respectively
$C H_{3} C O O H + N H_{3} \to X + ∆ \to Y + H_{2} O$

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${C H}_{3} {C O N H}_{2}; {C H}_{4}$

${C H}_{3} {C O O N H}_{4}; {C H}_{3} {C O N H}_{2}$

${C H}_{3} {C O N H}_{2}; {C H}_{3} C O O H$

${C H}_{3} {N H}_{2}; {C H}_{3} {C O N H}_{2}$

answer is B.

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Detailed Solution

Here, acetic acid reacts with ammonia to form ammonia acetate. And further this ammonia acetate on heating yields acetamide and water.

The following reaction equations are,

$C H_{3} C O O H + N H_{3} \to C H_{3} C O O^{-} N {H_{4}}^{+} C H_{3} C O O^{-} N {H_{4}}^{+} \overset{∆}{\to} C H_{3} C O N H_{2} + H_{2} O$

Hence, $X$ is ${C H}_{3} {C O O}^{-} {N H}_{4}^{+}$ and $Y$ is ${C H}_{3} {C O N H}_{2}$

Therefore, option (B) is correct.

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