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Q.

In the following redox equation xU2+ + Cr2O72-+ yH+ →aUO22+ + zCr3++bH2O the values of coefficients x, y and z are respectively

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a

3, 2, 4

b

3, 1, 8

c

3, 16, 4

d

3, 8, 7

answer is A.

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Detailed Solution

xU2+ + Cr2O72-+ yH+ →aUO22+ + zCr3++bH2O
 

\large \begin{array}{*{20}{c}} {RHR} \\ {C{r_2}O_7^{ - 2}\; \to \;2C{r^{ + 3}}} \\ {Balancing\;'O'\;atom} \\ {C{r_2}O_7^{ - 2}\; \to \;2C{r^{ + 3}}\; + \;7{H_2}O} \\ {Balancing\;H - atom\;in\;acidic\;medium} \\ {C{r_2}O_7^{ - 2}\;+14{H^+} \to \;2C{r^{ + 3}}\; + \;7{H_2}O} \\ {Balancing\;ch\arg e} \\ {C{r_2}O_7^{ - 2}\; + \;14{H^ + }\; + 6\bar e\; \to \;2C{r^{ + 3}}\; + \;7{H_2}O} \end{array}\left| {\begin{array}{*{20}{c}} {OHR} \\ {{U^{ + 2}}\; \to \;UO_2^{ + 2}} \\ {Balancing\;'O'\;atoms} \\ {{U^{ + 2}}\; + \;2{H_2}O\; \to \;UO_2^{ + 2}} \\ {Balancing\;H - atom\;in\;acidic\;medium} \\ {{U^{ + 2}}\; + \;2{H_2}O\; \to \;UO_2^{ + 2}\; + 4{H^ + }} \\ {Balancing\;ch\arg e} \\ {{U^{ + 2}}\; + \;2{H_2}O\; \to \;UO_2^{ + 2}\; + \;4{H^ + }\; + \;4\bar e} \end{array}} \right.


 

\large \begin{array}{*{20}{c}} {(RHR)\; \times 4\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;4C{r_2}O_7^{ - 2}\; + 56{H^ + } + \;24\bar e\; \to \;8C{r^{ + 3}}\; + \;28{H_2}O} \\ {(OHR)\; \times 6\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;6{U^{ + 2}}\; + \;12{H_2}O\; \to \;6UO_2^{ + 2}\; + 24{H^ + }\; + \;24\bar e} \\ {\overline {\underline {Net\;reaction\;\;4C{r_2}O_7^{ - 2}\; + \;6{U^{ + 2}}\; + \;32{H^ + }\; \to \;8C{r^{ + 3}}\; + \;6UO_2^{ + 2}\; + \;16{H_2}O} } } \end{array}


 

Question Image

 

 


x,y,z are 3,16,4 respectively

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