In the following sequence of reactions,
${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{OH}\stackrel{{\mathrm{P}}_4+{\mathrm{I}}_2}{\to }\mathrm{A}\stackrel{\mathrm{Mg}}{\to }\mathrm{B}\stackrel{\mathrm{HCHO}}{\to }\mathrm{C}\stackrel{{\mathrm{H}}_2\mathrm{O}}{\to }\mathrm{D}$

The compound ‘D’ is

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