In the following sub questions choose the correct answer from among the following possibilities and express the final answer as sum of the numbers
(P) The most stable low valent halide $(1) {GeX}_{2} (2) {SnX}_{2} (3) {PbX}_{2}$
(Q) A non existing halide $(1) {SnCl}_{4} (2) {PbCl}_{4} (3) {PbI}_{4}$
(R) A purely acidic oxide $(1) {PbO}_{2} (2) {SnO}_{2} (3) {SiO}_{2}$
(S) Thermally most stable hydride $(1) {NH}_{3} (2) {PH}_{3} (3) {AsH}_{3}$

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answer is 10.

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Detailed Solution

P) In a group the tendency to exhibit inert pair effect increase downwards = 3
Q) PbI₄: because of more polarazability of I^– it act as reducing agent= 3
R) SiO₂: PbO₂ and SnO₂ are amphoteric in nature=3
S) NH₃: In VA group hydrides the M-H bond energy decrease down words the group
and thermal stability decreases = 1
$∴$ 3+3+3+1=10

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