In the formation of a homo diatomic neutral molecule, if ' N ' atomic orbitals combine, then the total number of bonding molecular orbital formed is

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N/4

N/2

answer is C.

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Detailed Solution

We know the no. of molecular orbital formed is equal to the total no. combined atomic orbitals. Therefore, if N number of atomic orbitals combine together then we get N molecular orbitals & out of which N/2 is bonding & N/2 anti bonding. 80 , the total no. of bonding molecular orbitals formed is N/2.

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