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In the formation of R₃P=O, R₃P= CH₂ , P₄O₁₀ the $π$ bonding between 'P' and the other atom is

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$dπ - pπ$

$dπ - dπ$

can't be predicted

$pπ - pπ$

answer is B.

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Detailed Solution

P(Z=15) -

In R₃P=O, R₃P= CH₂ & P₄O₁₀hybridisation of 'P' is sp^3.. It forms $dπ - pπ$ bonds with oxygen and carbon in the given compounds

Carbon & Oxygen do not have d- orbitals.

They cannot utilize d-orbitals in pi-bonding.

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