Q.

In the given figure ΔABC  andΔDBC  are inscribed in a circle such that BAC=60°  and DBC=50° , thenBCD  is

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a

80°

b

60°

c

70°

d

50°

answer is C.

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Detailed Solution

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BDC=BAC [Angles in same segment]

BDC=60°

In ΔBDC ,BDC+DCB+CBD=180°

60°+DCB+50°=180°DCB=180°110°=70°

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